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Op 15-04-10 13:27, Nafees Ur Rehman schreef:

Whats is the syntax of grouping sets in monetdb? I am trying /Select has_nurs,form,health,class,count(*) from nursery group by GROUPING SETS ((has_nurs,class),(form,class),(health,class))/ but it does not work

It does not seem to be defined in SQL92 http://www.contrib.andrew.cmu.edu/~shadow/sql/sql1992.txt, thus it is not (yet) supported. Probably the best thing to do is to add a feature request on Sourceforge for it.

Stefan

Thanks for the tip.

Regards

Nafees

On Thu, Apr 15, 2010 at 04:27:55AM -0700, Nafees Ur Rehman wrote:

Hi,

Whats is the syntax of grouping sets in monetdb? I am trying Select has_nurs,form,health,class,count(*) from nursery group by GROUPING SETS ((has_nurs,class),(form,class),(health,class)) but it does not work

As far as I know, MonetDB does not support "GROUPING SETS" (yet?). Hence, you'd have to rewrite your query to "UNION ALL" several queries that do the individual groupings; e.g., your example:

SELECT has_nurs,form,health,class,count(*) FROM nursery GROUP BY GROUPING SETS ((has_nurs,class),(form,class),(health,class))

as follows:

SELECT has_nurs,form,health,class,count(*) FROM nursery GROPU BY has_nurs,class UNION ALL SELECT has_nurs,form,health,class,count(*) FROM nursery GROPU BY form,class UNION ALL SELECT has_nurs,form,health,class,count(*) FROM nursery GROPU BY health,class;

Feel free to file a feature request in case you would like to see "GROUPING SETS" in some future release of MonetDB/SQL (tough I cannot make any promises right now ...)

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